Decrementing step for loop I matlab
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y = zeros(1,12);
for i = 1:12
y(i+1) = y(i) + ((5 - (4/50)*y(i)));
end
y
x = zeros(1,10);
for i = 10:-1:2
x(i-1) = x(i) + ((5 + (4/50)*x(i)));
end
x
Good Day,
May I ask how can I insert the start and stop variable on above code? for example I want to start in 17 to 30 or 15 to 2 with decrementing step.
Thanks and Regards,
Dennis
0 Kommentare
Antworten (1)
Awais Saeed
am 24 Aug. 2021
Bearbeitet: Awais Saeed
am 24 Aug. 2021
% start, step, and end points
starty = 1;
endy = 12;
startx = 10;
endx = 2;
decrement = -1;
y = zeros(1,12);
for i = starty:endy
y(i+1) = y(i) + ((5 - (4/50)*y(i)));
end
y
x = zeros(1,10);
for i = startx:decrement:endx
x(i-1) = x(i) + ((5 + (4/50)*x(i)));
end
x
3 Kommentare
Awais Saeed
am 24 Aug. 2021
Bearbeitet: Awais Saeed
am 24 Aug. 2021
I am having difficulty in trying to understand your question. Do you want your first loop to start from 17 or 20 and end at 30 or 45? If that is the case just do
starty = 17;
endy = 30;
Same goes for the second loop. 'starty' and 'endy' are variables.
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