Hi, is it possible to extract a subgraph by selecting the edges, instead of nodes? If Yes, how?
From the Matlab docs, I can see it is possible by selecting the nodes, but not the edges:
H = subgraph(G,nodeIDs)
H = subgraph(G,idx)

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Wan Ji
Wan Ji am 20 Aug. 2021
Bearbeitet: Wan Ji am 21 Aug. 2021

1 Stimme

Note that all the endnodes of some given edges may be repeated, as commented by @Sim. Unique is a good way to solve such problem, to the example provided by Sim, now the code is modified as
clc; close all; clear all;
s = [1 1 1 1 2 2 2 2 2 2 2 2 2 2 15 15 15 15 15];
t = [2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20];
x = [1 2 0 0 0 1 7 8 9 10 1 2 4 3 5 6 7 8 9 10];
y = [0 1 0 1 2 2 0 1 2 3 4 5 3 5 6 3 4 6 7 8];
G = graph(s,t);
G.Nodes.X = x(:);
G.Nodes.Y = y(:);
EdgeNumber = [1 2 15] ; % the no. of egde
EndNodes = G.Edges.EndNodes(EdgeNumber,:)
H = subgraph(G, unique(EndNodes));
figure
hold on
plot(G,'XData',x,'YData',y,'EdgeColor','blue','LineWidth',1)
h = plot(H,'XData',H.Nodes.X,'YData',H.Nodes.Y,'EdgeColor','red','LineWidth',2);
h.NodeLabel = {};
It is found that this method includes one edge more, i.e. the edge (2,15) in G. This is OK, because what the method provide is the subgraph connected with these 5 nodes.
IF YOU WANT TO get subgraph really by edges. Then
s = [1 1 1 1 2 2 2 2 2 2 2 2 2 2 15 15 15 15 15];
t = [2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20];
x = [1 2 0 0 0 1 7 8 9 10 1 2 4 3 5 6 7 8 9 10];
y = [0 1 0 1 2 2 0 1 2 3 4 5 3 5 6 3 4 6 7 8];
G = graph(s,t);
G.Nodes.X = x(:);
G.Nodes.Y = y(:);
EdgeNumber = [1 2 15] ; % the no. of egde
EndNodes = G.Edges.EndNodes(EdgeNumber,:);
[q, ~, ic]= unique(EndNodes);
p = 1:1:numel(q);
st = p(reshape(ic,size(EndNodes)));
sub_Graph_by_Egde = graph(st(:,1), st(:,2));
sub_Graph_by_Egde.Nodes.X = G.Nodes.X(q,:);
sub_Graph_by_Egde.Nodes.Y = G.Nodes.Y(q,:);
figure
hold on
plot(G,'XData',x,'YData',y,'EdgeColor','blue','LineWidth',1)
h = plot(sub_Graph_by_Egde,'XData',sub_Graph_by_Egde.Nodes.X,...
'YData',sub_Graph_by_Egde.Nodes.Y,'EdgeColor','red','LineWidth',2);
I think I have solved your problem

3 Kommentare

Sim
Sim am 20 Aug. 2021
Bearbeitet: Sim am 20 Aug. 2021
Cool, many thanks @Wan Ji !
However, this works only with 1 edge:
clc; close all; clear all;
s = [1 1 1 1 2 2 2 2 2 2 2 2 2 2 15 15 15 15 15];
t = [2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20];
x = [1 2 0 0 0 1 7 8 9 10 1 2 4 3 5 6 7 8 9 10];
y = [0 1 0 1 2 2 0 1 2 3 4 5 3 5 6 3 4 6 7 8];
G = graph(s,t);
G.Nodes.X = x(:); G.Nodes.Y = y(:);
EdgeNumber = [10] ; % the no. of egde
EndNodes = G.Edges.EndNodes(EdgeNumber,:)
H = subgraph(G, EndNodes);
figure
hold on
plot(G,'XData',x,'YData',y,'EdgeColor','blue','LineWidth',1)
h = plot(H,'XData',H.Nodes.X,'YData',H.Nodes.Y,'EdgeColor','red','LineWidth',2);
h.NodeLabel = {};
Which gives me this result:
EndNodes =
2 11
How to make it work for many EdgeNumber ?
Sim
Sim am 21 Aug. 2021
Fantastic @Wan Ji, you totally nailed it! Very grateful!
Issue solved! :-)
Jothimani V
Jothimani V am 25 Jun. 2023
hello sir
how to split subgraphs(by selected edges) from given complete graph in matlab sir?

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Weitere Antworten (1)

Wan Ji
Wan Ji am 20 Aug. 2021

1 Stimme

hi, friend, you can make EdgeNumber an array that contains all the edge numbers that you are interested in. and make the line H = subgraph(G, EndNodes); changed as H = subgraph(G, EndNodes(:));

3 Kommentare

Sim
Sim am 20 Aug. 2021
Bearbeitet: Sim am 21 Aug. 2021
Hi, thanks for the nice reply... I used
H = subgraph(G, unique(EndNodes));
instead of your suggestion:
H = subgraph(G, EndNodes(:));
since, with your hint, it gave me the following error:
Error using graph/subgraph (line 40)
Nodes must be a vector of unique node indices, a vector of unique node names, or a logical vector of length equal to the number of
nodes.
Now it works, but there is still an important issue to fix.
In this example:
clc; close all; clear all;
s = [1 1 1 1 2 2 2 2 2 2 2 2 2 2 15 15 15 15 15];
t = [2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20];
x = [1 2 0 0 0 1 7 8 9 10 1 2 4 3 5 6 7 8 9 10];
y = [0 1 0 1 2 2 0 1 2 3 4 5 3 5 6 3 4 6 7 8];
G = graph(s,t);
G.Nodes.X = x(:); G.Nodes.Y = y(:);
EdgeNumber = [1 2 15] ; % the no. of egde
EndNodes = G.Edges.EndNodes(EdgeNumber,:)
H = subgraph(G, unique(EndNodes));
figure
hold on
plot(G,'XData',x,'YData',y,'EdgeColor','blue','LineWidth',1)
h = plot(H,'XData',H.Nodes.X,'YData',H.Nodes.Y,'EdgeColor','red','LineWidth',2);
h.NodeLabel = {};
the result is:
EndNodes =
1 2
1 3
15 16
However, in the subgraph H I have an additional edge, i.e 4 edges, instead of 3 edges:
>> H.Edges
ans =
1 2
1 3
2 4
4 5
which can be seen in the following picture too (here, the nodes labels refer to G and not to H):
This is due to the fact that I had to take the unique nodes in G, as required by the subgraph function:
H = subgraph(G,nodeIDs)
i.e.
>> unique(EndNodes)
ans =
1
2
3
15
16
In summary, this method includes one edge more, i.e. the edge (2,15) in G:
EndNodes =
1 2
1 3
2 15
15 16
If we can solve this issue it is done!
Wan Ji
Wan Ji am 20 Aug. 2021
yes, you have done a good job, 👍👍👍
Sim
Sim am 21 Aug. 2021
many thanks @Wan Ji! :)

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Sim
am 20 Aug. 2021

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