cell2mat -> operation -> mat2cell : How...?

8 Ansichten (letzte 30 Tage)
William Thielicke
William Thielicke am 19 Aug. 2021
Hi, I have a cell aray that I need to convert to a 3D matrix, perform some operation, and then convert it back to the original cell format. I am failing to do te last step:
for i=1:301 % generate the cell array example dataset
u{1,i}=rand(41,50);
end
u_3d=reshape(cell2mat(u),size(u{1},1),size(u{1},2),size(u,2)); %convert cell array to 3D matrix
u_3d=medfilt3(u_3d); %perform an operation
u_3d=reshape(u_3d, size(u{1},1) , size(u{1},2)*size(u,2)); %reshape
% ... and convert back to cell array in original format... I don't get what
% numbers I have to enter...
bla=mat2cell(u_3d,[41 50],301); %Error
Thanks for your help!

Akzeptierte Antwort

Adam Danz
Adam Danz am 19 Aug. 2021
Bearbeitet: Adam Danz am 19 Aug. 2021
for i=1:301 % generate the cell array example dataset
u{1,i}=rand(41,50);
end
u_3d = cat(3,u{:});
u_3dFilt = medfilt3(u_3d); %perform an operation
u_cell = squeeze(num2cell(u_3dFilt, [1,2]))';
Confirm output
% check that it's a 1x301 cell
whos('u_cell')
Name Size Bytes Class Attributes u_cell 1x301 4967704 cell
% Spot-check that cell n matches u_3dFilt(:,:,n)
isequal(u_cell{10}, u_3dFilt(:,:,10))
ans = logical
1

Weitere Antworten (0)

Kategorien

Mehr zu Data Type Conversion finden Sie in Help Center und File Exchange

Produkte


Version

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by