How can i call the value of another variable defined or solved above for solving another equation?

4 Ansichten (letzte 30 Tage)
Right now, I have a 6-order polynomial expression, it has only one variable.
I want to be able to call values of some variable defined or obtained above, and solve the polynomial equation for different values of the expression.
I used the following code, but it does not work.
p(1)=1,p(2)=2,p(3)=3,p(4)=4,p(5)=5,p(6)=6,p(7)=7;
f(1)=1,f(2)=2,f(3)=3,f(4)=4,f(5)=5,f(6)=6,f(7)=7;
solve('p(1)*(x.^6)+p(2)*(x.^5)+p(3)*(x.^4)+p(4)*(x.^3)+p(5)*(x.^2)+p(6)*x+ p(7)=f(1)');
what mistake have I made? or in what ways can achieve this purpose?
Thank you.

Akzeptierte Antwort

Roger Stafford
Roger Stafford am 23 Jul. 2014
Bearbeitet: Roger Stafford am 23 Jul. 2014
Instead of using 'solve' try using 'roots' for numerical solutions. It will be much faster.
Also, 'solve' will in general be unable to find symbolic solutions for sixth order polynomials.
  1 Kommentar
zy
zy am 24 Jul. 2014
Thank you very much, 'roots' works.
Since it is a 6 order polynomial equation, there may be up to 6 roots including real roots and complex roots.
Can I do something to filter or pick up only real roots?

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Matz Johansson Bergström
Matz Johansson Bergström am 23 Jul. 2014
Bearbeitet: Matz Johansson Bergström am 23 Jul. 2014
Try
syms x
p = 1:7;
f = 1:7;
solve(p(1)*x^6+p(2)*x^5+p(3)*x^4+p(4)*x^3+p(5)*x^2+p(6)*x+p(7)==f(1), x)

Kategorien

Mehr zu Polynomials finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by