Help on Disappearing Popupmenu
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Franco
am 14 Jul. 2014
Kommentiert: Franco
am 14 Jul. 2014
So I've created a GUI with a popupmenu, but it seems that whenever I try to populate the menu, it disappears, anyone know what going on. Thanks in advance. Heres an example of what I am trying to do.
var1 = {'Ex1','Ex2','Ex3'}
for i =1:length(var1)
set(handles.popupmenu1,'String',var1(i),'Value',i)
end
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Akzeptierte Antwort
Image Analyst
am 14 Jul. 2014
That code you gave will give you a single item (the last one) in the popup. Do not use a for loop. The items in a popup or listbox are not entered in one at a time like you tried, they are done all at once with a single call to set the string property. What you did was to set the entire list to just a single item, and you did it 3 times (once on each iteration of your for loop). Since there is only one item in there, and the value is now 3 (which is more than 1), the popup will not display.
To fix, send in all the items in one shot, then set the value.
var1 = {'Ex1', 'Ex2', 'Ex3'}
set(handles.popupmenu1, 'String', var1); % Send in all 3 items at once.
set(handles.popupmenu1, 'Value', length(var1)); % Set what item is selected (the last one).
Weitere Antworten (1)
Azzi Abdelmalek
am 14 Jul. 2014
Bearbeitet: Azzi Abdelmalek
am 14 Jul. 2014
Why the for loop?
var1 = {'Ex1','Ex2','Ex3'}
i=1
set(handles.popupmenu1,'String',var1,'Value',i)
4 Kommentare
Image Analyst
am 14 Jul. 2014
Azzi's code is correct. If it doesn't work, then do it in two separate steps, set the string first, and then the value. Do not use a for loop. The items are not entered in one at a time like you tried, they are done all at once with a single call to set the string property.
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