Plot in complex plane - Symbolic toolbox

3 Ansichten (letzte 30 Tage)
Alex Ter-Sarkissov
Alex Ter-Sarkissov am 18 Aug. 2011
I'm trying to plot the function of complex variable:
mu:=10;lambda:=mu;n:=100;
f2:=16*mu*n^2/(16*mu*n^2-exp(-9*lambda*(n^2-4*k^2)/(64*n^2)))
plot(f2,Re(k)=0..100,Im(k)=0..100,#3D)
and keep getting this message: Error: unexpected arguments: Re(k) = 0..100, Im(k) = 0..100 [plot::Canvas::new]
what am I doing wrong?

Antworten (2)

Paulo Silva
Paulo Silva am 19 Aug. 2011
That doesn't look like MATLAB code, are you using MUPAD instead?
  6 Kommentare
Alex Ter-Sarkissov
Alex Ter-Sarkissov am 19 Aug. 2011
I tried plot(Im(f2),k=0..100,#3D) and plot(Im(f2),k=I*0..I*100,#3D) instead but is definitely not what I'm having in mind
Paulo Silva
Paulo Silva am 19 Aug. 2011
sorry but I have no idea how to do it but someone else might, good luck

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Walter Roberson
Walter Roberson am 19 Aug. 2011
mu:=10;lambda:=mu;n:=100;
f2:=16*mu*n^2/(16*mu*n^2-exp(-9*lambda*(n^2-4*(k+j*I)^2)/(64*n^2)));
plotfunc3d(f2,k=0..100,j=0..100);
  5 Kommentare
Walter Roberson
Walter Roberson am 19 Aug. 2011
Any particular reason not to specify the contour levels as (say) -1e10 -1e9 -1e8 -1e7 ... 1e7 1e8 1e9 1e10 ?
Having it choose automatic contour levels might be more difficult.
I do not have the Symbolic Toolbox and have not used MuPad graphics myself, so I do not know the standard idioms.
Alex Ter-Sarkissov
Alex Ter-Sarkissov am 20 Aug. 2011
OK, how do you plot complex functions then?

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