What should be modified inside the for loop?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
For each value of f_x_loop, I need x_a to take one of the five values from s_x_index for each iteration instead of one value for all the iteration.
s_x_index=[0.01 0.02 0.03 0.04 0.05]
for i = 1:length(s_x_index)
x_a = s_x_index(i);
f_x_loop = (F*x_a)/(s*Q)
f_x_loop_save(i) = f_x_loop(i)
end
Please let me know if the given information is not sufficient.
Thanks
0 Kommentare
Akzeptierte Antwort
Sara
am 2 Jul. 2014
Change these lines:
f_x_loop = (F*x_a)/(s*Q)
f_x_loop_save(i) = f_x_loop(i)
into:
f_x_loop_save(i) = (F*x_a)/(s*Q)
in addition, put:
f_x_loop_save = zeros(numel(s_x_index),1);
before the for loop
5 Kommentare
Joseph Cheng
am 2 Jul. 2014
Bearbeitet: Joseph Cheng
am 2 Jul. 2014
At the start before you do their suggestion just do mine. what i suggest will get it so that all your values are not for one value on the X axis.
what was originally suggested is good practice as you're doing an un-necessary temporary calculation (b=a then c=b, why not just c=a since you aren't using b anywhere) and initialization of the array for memory optimization (faster to fill in matrix than keep adding to the end of an array).
Sara
am 3 Jul. 2014
Try this:
f_x = (F.*s_x_index)/(s*Q);
figure(5);
plot(s_x_index, f_x, 'o')
xlabel('Longitudinal creepage');ylabel('coefficient of adhesion')
hold on;
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!