separating object and bacground with imsubtract
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how to separating object and background with imsubstract??
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Image Analyst
am 17 Aug. 2011
How about
subtractedImage = single(originalImage) - single(backgroundImage);
2 Kommentare
Image Analyst
am 18 Aug. 2011
Because backgroundImage is on the RIGHT side of the equation, not the left side. So the background image does not change. If you're saying that the subtractedImage does not change then you'll have to provide sample images (originalImage and backgroundImage) and code that proves that subtractedImage does not change. It should change - the only way it wouldn't change is if backgroundImage were all zeros. Just a guess . . . you DID remember to cast your integer images into single or double like I showed you, right? Otherwise you'll get clipping of the negative numbers to zero.
Alex Taylor
am 31 Jan. 2012
I just wanted to add, as whenever this issue comes up, that Image Analyst's solution of using the MATLAB minus operator instead of imsubtract is the recommended way to perform basic math operations on images in MATLAB.
The IPT versions of these math operations (imadd, imsubtract, immultiply, imdivide) predate the support for non-double math operations in core MATLAB. We leave them in the product primarily for compatibility purposes.
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