rectangularPulse: no drop to 1/2 at edges

1 Ansicht (letzte 30 Tage)
T
T am 27 Jun. 2014
Bearbeitet: Matthew Suttinger am 30 Mär. 2018
Hello I want to do the fourier of a rectangular pulse which is also 1 at the edges, so that the fourier returns a sinc function. rectangularPulse drops to 1/2 at the edges and does not seem to return the equivalent function if I plot the result vs. a sinc function. I tried ceil but this is not accepted with the fourier function.
Thanks a lot!

Antworten (2)

Image Analyst
Image Analyst am 27 Jun. 2014
So just create it manually
myPulse = [0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ];
  2 Kommentare
Image Analyst
Image Analyst am 27 Jun. 2014
Bearbeitet: Image Analyst am 27 Jun. 2014
T's "Answer" moved here since it's not an answer to the original question.
I can't, the width of the rectangular pulse depends on a syms variable :/ And besides that, I dont think fourier(myPulse,f,y) would work then anymore anyway.
Image Analyst
Image Analyst am 27 Jun. 2014
Make it depend on the variable:
signalLength = 512; % whatever.
myPulse = zeros(1, signalLength);
startingIndex = 20; % Whatever
pulseWidth = 64; % Whatever, e.g. your syms variable value.
myPulse(startingIndex:(startingIndex + pulseWidth - 1)) = 1;

Melden Sie sich an, um zu kommentieren.


Matthew Suttinger
Matthew Suttinger am 30 Mär. 2018
Bearbeitet: Matthew Suttinger am 30 Mär. 2018
If you don't mind converting it to a double after applying inputs, wrap the result in the ceil() function.
y = ceil(rectangularPulse(x_start,x_end,x_values));
class(y) % ans = 'double'

Kategorien

Mehr zu Get Started with MATLAB finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by