select the row that contains the minimum of a column

11 Ansichten (letzte 30 Tage)
dolving
dolving am 27 Jun. 2014
Beantwortet: Star Strider am 27 Jun. 2014
I have this matrix:
results =
0.0260 0.1040 0.0030 0.0246 0.0264 4.8818
0.0430 0.1040 0.0030 0.0194 0.0238 5.0857
0.0600 0.1040 0.0030 0.0164 0.0223 5.2897
0.0260 0.0870 0.0030 0.0245 0.0263 5.0856
0.0430 0.0870 0.0030 0.0194 0.0237 5.2896
0.0600 0.0870 0.0030 0.0167 0.0221 5.4936
0.0260 0.0700 0.0030 0.0246 0.0259 5.2896
0.0430 0.0700 0.0030 0.0194 0.0233 5.4937
0.0600 0.0700 0.0030 0.0164 0.0217 5.6976
0.0260 0.1040 0.0065 0.0331 0.0413 0
0.0430 0.1040 0.0065 0.0269 0.0322 4.0227
0.0600 0.1040 0.0065 0.0207 0.0264 4.4647
0.0260 0.0870 0.0065 0.0330 0.0409 0
0.0430 0.0870 0.0065 0.0268 0.0319 4.4648
0.0600 0.0870 0.0065 0.0208 0.0261 4.9067
0.0260 0.0700 0.0065 0.0330 0.0397 4.4648
0.0430 0.0700 0.0065 0.0269 0.0306 4.9067
0.0600 0.0700 0.0065 0.0208 0.0249 5.3487
0.0260 0.1040 0.0100 NaN 0 0
0.0430 0.1040 0.0100 0.0578 0.0639 0
0.0600 0.1040 0.0100 0.0445 0.0423 0
0.0260 0.0870 0.0100 NaN 0 0
0.0430 0.0870 0.0100 0.0577 0.0628 0
0.0600 0.0870 0.0100 0.0446 0.0411 0
0.0260 0.0700 0.0100 NaN 0 0
0.0430 0.0700 0.0100 0.0576 0.0584 0
0.0600 0.0700 0.0100 0.0445 0.0367 4.8460
I want to select the row that contains the minimum nonzero value of the last column.
I tried:
[minVal rowInd]=min(nonzeros(results(:,6)))
minVal =
4.0227e+003
row_idx =
10
This does give the value i want, but not the right row (it must be row_idx=11).
Any ideas would be welcome!!

Akzeptierte Antwort

Guilherme Coco Beltramini
Guilherme Coco Beltramini am 27 Jun. 2014
Use an auxiliary variable:
tmp = results(:,6); tmp(tmp==0) = NaN;
[minVal rowInd]=min(tmp)

Weitere Antworten (1)

Star Strider
Star Strider am 27 Jun. 2014
Test for the minimum first, then use find:
min6 = min(results((results(:,6) > 0),6));
ridx = find(results(:,6) == min6);

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