Hi all,
probably a very simple question..I need to read a text file consisting of a list of vectors with this format:
skip the first 22 line and then (x y z) (x y z) (x y z) ... (x y z)
there are 263853 line. How can i do that??
thanks for any help
andrea

Antworten (3)

Jan
Jan am 15 Feb. 2011

1 Stimme

The description of the file format is not exact enough. I'll show you a method for a well defined format and I assume you can adjust it to your needs:
I assume the file looks like this:
Header line 1
...
Header line 22
(0.1 0.2 0.3)
(0.17 19.5 231)
... <263853 of such lines>
This can be solved by TEXTSCAN or more low-levelish:
FID = fopen(FileName, 'r');
if FID <= 0, error('Cannot open file'); end
for iSkip = 1:22
dummy = fgetl(FID);
end
Data = fscanf(FID, '(%g %g %g)\n');
Data = transpose(reshape(Data, 3, []));
fclose(FID);

2 Kommentare

Andrea Ferrari
Andrea Ferrari am 15 Feb. 2011
thanks Jan. It runs
andrea
Jan
Jan am 15 Feb. 2011
Thanking is very polite. Accpeting an answer is helpful for others in addition.

Melden Sie sich an, um zu kommentieren.

Andrea Ferrari
Andrea Ferrari am 15 Feb. 2011

0 Stimmen

sorry
all vector are in column (not along a line).
andrea
Matt Tearle
Matt Tearle am 15 Feb. 2011

0 Stimmen

Or, using textscan (as Jan mentioned):
FID = fopen(FileName, 'r');
if FID <= 0, error('Cannot open file'); end
Data = textscan(FID, '(%f %f %f)','headerlines',22);
x = Data{1};
y = Data{2};
z = Data{3};
fclose(FID);

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