Ältere Kommentare anzeigen
Hi all,
probably a very simple question..I need to read a text file consisting of a list of vectors with this format:
skip the first 22 line and then (x y z) (x y z) (x y z) ... (x y z)
there are 263853 line. How can i do that??
thanks for any help
andrea
Antworten (3)
Jan
am 15 Feb. 2011
The description of the file format is not exact enough. I'll show you a method for a well defined format and I assume you can adjust it to your needs:
I assume the file looks like this:
Header line 1
...
Header line 22
(0.1 0.2 0.3)
(0.17 19.5 231)
... <263853 of such lines>
This can be solved by TEXTSCAN or more low-levelish:
FID = fopen(FileName, 'r');
if FID <= 0, error('Cannot open file'); end
for iSkip = 1:22
dummy = fgetl(FID);
end
Data = fscanf(FID, '(%g %g %g)\n');
Data = transpose(reshape(Data, 3, []));
fclose(FID);
2 Kommentare
Andrea Ferrari
am 15 Feb. 2011
Jan
am 15 Feb. 2011
Thanking is very polite. Accpeting an answer is helpful for others in addition.
Andrea Ferrari
am 15 Feb. 2011
0 Stimmen
Matt Tearle
am 15 Feb. 2011
Or, using textscan (as Jan mentioned):
FID = fopen(FileName, 'r');
if FID <= 0, error('Cannot open file'); end
Data = textscan(FID, '(%f %f %f)','headerlines',22);
x = Data{1};
y = Data{2};
z = Data{3};
fclose(FID);
Kategorien
Mehr zu Text Data Preparation finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!