Add up a certain number of consecutive values followed by the next values in a row

Good morning,

I am looking for a function that can do the following:

E.g.

A = [1 3 4 0 -1 6]

Result = 4 4 5

Always added up two values from the beginning - then the next two values - and so on.

It would be nice to have the option to say please always add up 3 values, so that the result would be: Result = 8 5

Thanks for your help!

Dennis

Answer 1

[Wan Ji]

I'll write for you!

function a = everynsum(arr, n)
p = length(arr);
a = sum(reshape(arr,n,p/n)); % in case mod(p,n)=0
end

[Wan Ji]

By movsum you can do:

A = [1 3 4 0 -1 6];
n = 2; % every 2 sum
B = movsum(A,n);
Result = B(n:n:end)

The result is

Result =

     4     4     5

[Dennis Annutsch]

Thank you very much!! This works exactly as I imagined. I wish you all the best!

Answer 2

[Awais Saeed]

clc;clear all;close all
A = [1 3 4 0 -1 6];
n = 2;  % sum every n elements
jj = 0;
simdone = true; % to keep while loop running

while (simdone)
 jj = jj + 1;
 if (size(A,2) == n)
  result(jj) = sum(A(1:n));
  break % break while loop
 end

 result(jj) = sum(A(1:n));
 A(1:n) = [];   % deleting summed elements
end

[Dennis Annutsch]

Thanks for the quick help!