How to use for loop to get the minimum number in an array
4 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Grace
am 16 Jun. 2014
Beantwortet: Jos (10584)
am 16 Jun. 2014
For simplicity, I have
A=[ 11 7 10 9 6 4 3]
and
B=8
I want to have a for loop to compare each of the elements in A with the latest minimum number from the for loop to get the final minimum number in A.
For example, when A(1) compare with B, min=8, then i continue with the A(2) compare with min=8, this time min=7. After that, A(3) compare with min=7, new min=7. The steps continue till the last elements of A.
0 Kommentare
Akzeptierte Antwort
Jos (10584)
am 16 Jun. 2014
A = [ 11 7 10 9 6 4 3]
B = 8
result = min([A B])
% or if you insist on using a for-loop (why?)
result = B
for k = 1:numel(A)
if A(k) < result,
result = A(k)
end
end
0 Kommentare
Weitere Antworten (1)
Abhishek M
am 16 Jun. 2014
Bearbeitet: Abhishek M
am 16 Jun. 2014
Hi Grace, I guess this is what you are expecting. Please find the demo example below.
a=[1:2:10];
b=4;
for i=1:5
if a(i)<b
min=b;
else
min=a(i);
end
end
0 Kommentare
Siehe auch
Kategorien
Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!