to make the rectangle move over the image

hai

i am new to matlab i doing a project for locating the optic disc for that i have create a rectangular window and make the window to move the image and calculate the sum of edge diff inside the window and divide that by sum of intensity inside the window

now i have created a window but i don't know how to move the rectangular window

this is my code please help me

_clc; clear all; close all; fundus=imread('D:\10mcs010\im0001.ppm'); grayImage=fundus(:,:,1);

 subplot(4, 4, 1);
 imshow(grayImage);
title('Original Grayscale Image');
binaryImage = grayImage > 35; 
% Display the binary image.
 subplot(4, 4, 2);
imshow(binaryImage);
title('Binary Image');
A=[0 0 0;0 1 0;0 0 0];
op=imopen(binaryImage,A);
subplot(4,4,3);
imshow(op);
title('open image');
clos=imopen(op,A);
subplot(4,4,4);
imshow(clos);
title('closeimage');
eror=imopen(clos,A);
subplot(4,4,5);
imshow(eror);
subplot(4,4,6);
 maskedRgbImage = bsxfun(@times, fundus, cast(eror,class(fundus)));
imshow(maskedRgbImage);
title('RGB IMAGE');
g=maskedRgbImage(:,:,2);
 subplot(4,4,7);
 imshow(g);
title ('Green component');
subplot(4,4,8);
 imv=conv2(double(g),[1 0 -1],'same');
 imshow((imv));
 title ('vertical image');
 subplot(4,4,9);
 imh=conv2(double(g),[1;0;-1],'same');
 imshow(imh);
 re=imh;
 imwrite(re,'horizontal.tif');
title ('horizontal image');
 edgesum=abs(imh)+abs(imv);
% % intens=impixel(fundus);
% 
% %  figure,imshow(edgesum);
% edgediff=abs(imv)-abs(imh);
   im = imread('horizontal.tif');
   subplot(4,4,10);
   imshow(im);
 r=rectangle('Position',[10,10,12,560]);
 set(r,'edgecolor','w') % change the color of the rectangle to white
title('image with rectangle');_

*BOLD TEXT*

[Walter Roberson]

duplicate is at http://www.mathworks.com/matlabcentral/answers/13866-move-rectangle-over-te-image

Answer 1

[Jason]

You can use imrect and use the mouse to size and move. It returns the position and size.

h = imrect;
pos = h.getPosition();

Jason

Answer 2

[Image Analyst]

How about using rbbox()? It lets your user draw a box. There's sample code in its help.

Answer 3

[ramya raj]

the rectangle can be created by using rectangle function

which take the syntax of rectangle(x,y,w,h) x - x coordinate y - y coordinate w - width of the rectangle h - height of the rectangle

Answer 4

[Walter Roberson]

This seems to me to be a make-work project. Moving a virtual array over the data array would be much much more efficient than drawing a rectangle on the screen and figuring out what is inside the drawn portion.