Hi, I have a matrix as follows:
I =
1 0 0 0 0 1
0 1 0 0 1 0
0 1 0 1 0 0
0 0 1 0 0 0
0 1 0 1 1 0
1 0 0 0 0 1
here 4 ones are in the total matrix boundary position. Is there any easy way that will return me the position of those pixel i.e. for this matrix (1,1),(6,1),(1,6),(6,6) thanks in advance.

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Friedrich
Friedrich am 10 Aug. 2011

0 Stimmen

Hi,
maybe this:
I =[
1 0 0 0 0 1
0 1 0 0 1 0
0 1 0 1 0 0
0 0 1 0 0 0
0 1 0 1 1 0
1 0 0 0 0 1 ];
[x y] = size(I);
tmp = zeros(x,y);
tmp(1,:) = ones(1,y);
tmp(x,:) = ones(1,y);
tmp(:,1) = ones(x,1);
tmp(:,y) = ones(x,1);
[i j] = find(I.*tmp == 1);
disp([i,j])

2 Kommentare

Mohammad Golam Kibria
Mohammad Golam Kibria am 10 Aug. 2011
Thanks
Andrei Bobrov
Andrei Bobrov am 10 Aug. 2011
a = eye(size(I))
a = a(:,end:-1:1)+a
a(2:end-1,2:end-1)=0
find(I & a)

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