Using sscanf and NaN
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Sebastian Ciuban
am 6 Jun. 2014
Kommentiert: Geoff Hayes
am 9 Jun. 2014
Greetings,
So if i have the following:
a = '21414839.260 112535757.19909 2294.184 21414838.320 87690207.10148 1787.672'
Using:
A=sscanf(a,'%f')
Will return:
A =
1.0e+08 *
0.2141
1.1254
0.0000
0.2141
0.8769
0.0000
But if If the last 3 numbers are missing from the line :
a = '21414839.260 112535757.19909 2294.184 '
I want this to be returned:
A =
1.0e+08 *
0.2141
1.1254
0.0000
NaN
NaN
NaN
How can I make this possible?
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Akzeptierte Antwort
Geoff Hayes
am 6 Jun. 2014
If you know that sscanf of the input string is to return 6 numbers, and A is only populated with three, then you could do the following
A = [A; repmat(NaN,6-length(A),1)];
16 Kommentare
Weitere Antworten (1)
Star Strider
am 6 Jun. 2014
Use sscanf with two output arguments:
% Known input length
L = 6;
a = '21414839.260 112535757.19909 2294.184'
[A, knt] = sscanf(a, '%f');
A(knt+1:L) = NaN;
produces:
A =
21.4148e+006
112.5358e+006
2.2942e+003
NaN
NaN
NaN
2 Kommentare
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