Simply Directory Question

Hello All,

Quick question, I am trying to load all files from a folder that have a .m ext:

folder = C:\Users\ecorbett\Documents\MATLAB\UI\VCoachData\0005_Capture_10072009\AccelData

files = dir(folder)

I know I need to include something like '*.m' in dir but I dont know the correct syntax to do so. Can someone help me with this?

Answer 1

[Paulo Silva]

m=dir([folder '\*.m']);
files=arrayfun(@(x)m(x).name,1:numel(m),'uni',false); %or use Oleg suggestion

[Oleg Komarov]

files = {m.name};

[Paulo Silva]

Thanks Oleg, I always forget that easy way to do it

[B_Richardson]

what is this "name?" Is that my "folder"?

[Oleg Komarov]

Check out the documentation for dir. Name is a field of the structure m.

[Walter Roberson]

No, in this context, "name" is a particular field from the structure returned by dir. m(K).name is the name of the K'th file, but without any parts of the folder name.

[Paulo Silva]

name is a field of the structure you get from the dir function, each file the dir function accepts creates a new entry on the structure with several fields, name being one of them.

[B_Richardson]

I see! Thank you all! I feel like you guys are my professors sometimes lol

[Walter Roberson]

Think I'd be able to get Tenure? ;-)

[B_Richardson]

You'd have my vote!

Answer 2

[B_Richardson]

Hey guys, I'm still having trouble with this code. I've included the some more to give you a better understanding of what I'm tring to do.

I just want to get a dir (load .mat data files only) and loop through that dir until I match my pattern. Once I match, load construct fullfile.

[pathstr, name, ext] = fileparts(file)
  name = 'AccelData';
  file2 = fullfile(pathstr,[name]) 
  z=dir([file2 '\*.m']); 
  files = {z.name}
  Pattern=itemselected(1:9)
  for  i = 1 : numel(files)
  value=files(i).name;
      if strfind(value,Pattern)
          f = fullfile(file2,value)

For some reason,

     z=dir([file2 '\*.m']); 
      files = {z.name}

files is coming up empty. The way I had it before worked:

files = dir(folder)

But of course it included all file types and i just want the matlab data files.

[Oleg Komarov]

z=dir([file2 '*.m']);

without the \

[B_Richardson]

Still comes up empty.

z=dir([file2])

works. But the'*.m' is messing it up

[B_Richardson]

0x1 struct array with fields:

name

date

bytes

isdir

datenum

[Oleg Komarov]

can you show what's file2?

Answer 3

[B_Richardson]

I feel so stupid right now! My files are .mat not .m! AARRRGGGGGG Thanks everybody!!