concatenating string variable names and passing on values of a matrix in a for loop

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Hi there,
I have many files, for each file I create variable names with part of the filename (using for loop and counter the filecounter) and then, I pass on to them the values of a matrix (AWFR) I create for each iteration, using eval()
The problem is that I want to concatenate all these column - vector variables into one large column vector, without having to type the names manually all over again, after these are saved in the workspace.
I managed to create a matrix containing all the names of the variables (AWFRallthenames), but I couldn't pass on the values with eval([AWFRallthenames(filecounter,:),'=AWFR']).
Is there any other way and why the above does not work? I am attaching a part of the code if that helps!!
Any help appreciated! Thank you
for filecounter=1:2%length(FileList)
% matrix allthenames keeps all the AWFR names (every hour,
%every .xdat file), in integer values
%and this converts the integer values to a string
%Now create the AWFR matrix. NO stimulation intervals included.
AWFR = zeros(nBins, 1);
for n=1:nBins
index_ofeach_bin=find( (Ts>(n-1)*(Fs*60*BinSize)) & (Ts<=n*(Fs*60*BinSize)))
%now I pass on the values to the string name I have created before (AWFRname)
%now I pass on the values of the string name I have created before, and
%rests in a row of the AWFRallthenames matrix
Stelina on 12 May 2014
Edited: Stelina on 12 May 2014
Hey Geoff,
Yes indeed the initial way I was trying to solve this was by keeping the integer values of the strings in the filecounter row of AWFRallthenames and then using char()to get the string names, but it produced the same results with eval([AWFRname],'=AWFR')
@dpb thanx for the links

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Accepted Answer

Roberto on 8 May 2014
Creating variable names via EVAL function is highly NOT RECOMMENDED. Try to use a different philosophy... try this for example:
% create your 'myVar' structure with all contents to store:
for fCounter = 1 : totalFiles
myVar(fCounter).datehour = BasicName(end-12:end) ;
myVar(fCounter).onoma1 = 'AWFR' ;
myVar(fCounter).onoma2 = myVar(fCounter).datehour ;
myVar(fCounter).AWFRname = horzcat(myVar(fCounter).onoma1,myVar(fCounter).onoma2) ;
myVar(fCounter).AWFR = zeros(nBins, 1);
for n=1:nBins
index_ofeach_bin = find( (Ts>(n-1)*(Fs*60*BinSize)) & (Ts<=n*(Fs*60*BinSize)));
myVar(fCounter).AWFR(n) = length(index_ofeach_bin);
% Process all elements
for i = 1 : numel(myVar)
disp(['AWFR name: ' myVar(i).AWFRname]);
% then you can save only one variable to workspace
In case you want to learn how to filter structures, to get just one element, have a good look in to this amazing video tutorial. Good luck!
  1 Comment
Stelina on 12 May 2014
Hey Roberto,
Thanx a lot both for the tutorial and the code!
Indeed, I made a structure, where I added two fields, one for keeping the names and the other the values, so I can concatenate easily. Much more straightforward this way!

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