How to rearrange the rows of a matrix?
104 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
MRC
am 28 Apr. 2014
Beantwortet: Roberto
am 28 Apr. 2014
Hi, I want to reshape a matrix A of dimension rxc in a matrix B of the same dimension but with rows rearranged following the index in the first column
E.g.
A=[ 1 1 4 7 10; 2 2 5 8 11; 3 3 6 9 12; 4 13 16 19 22; 5 14 17 20 23; 6 15 18 21 24; 1 25 26 27 28; 2 29 30 31 32; 3 33 34 35 36; 4 37 38 39 40; 5 41 42 43 44; 1 46 47 48 49; 2 50 51 52 53; 5 54 55 56 57; 6 58 59 60 61]
I want
B=[1 1 4 7 10; 1 25 26 27 28; 1 46 47 48 49; 2 2 5 8 11;2 29 30 31 32;2 50 51 52 53; 3 3 6 9 12; 3 33 34 35 36; 4 13 16 19 22; 4 37 38 39 40; 5 14 17 20 23; 5 41 42 43 44; 5 54 55 56 57; 6 15 18 21 24; 6 58 59 60 61]
The features of A on which I can rely are:
-the max of the first column is m=6;
-the elements in the first column of A are increasing until m and then they restart;
-each element of the first column of A can appear for at most n=3 times.
I prefer not to use loops.
0 Kommentare
Akzeptierte Antwort
Andrew Newell
am 28 Apr. 2014
The trick is to use the index from sorting the first column:
[~,idx] = sort(A(:,1));
B = A(idx,:);
0 Kommentare
Weitere Antworten (1)
Roberto
am 28 Apr. 2014
try accessing the matrices subscripts, for example:
% have this matrix
a =
16 2 3 13
5 11 10 8
9 7 6 12
4 14 15 1
% change the order of rows:
a([3 2 4 1],:)
ans =
9 7 6 12
5 11 10 8
4 14 15 1
16 2 3 13
0 Kommentare
Siehe auch
Kategorien
Mehr zu Matrices and Arrays finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!