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Date conversion in a number format

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Md
Md am 27 Mär. 2014
Kommentiert: Walter Roberson am 27 Mär. 2014
Hey guys
I have an excel file with the date format like this: '03/06/2014 11:39:04.324 PM' I want to convert this date format into (yyyymmddhhmmssSSS)20140306233904324. If the time is PM, then the hour should be in the format of 24 hours. Thanks in advance.

Akzeptierte Antwort

Chandrasekhar
Chandrasekhar am 27 Mär. 2014
clc
str = '03/06/2014 11:39:04.324 PM';
[date,rem] = strtok(str,'/');
[month,rem]= strtok(rem,'/');
[year,rem]=strtok(rem,' ');
year = regexprep(year,'/','');
[hours,rem]=strtok(rem,':');
hours = regexprep(hours,' ','');
[mins,rem] = strtok(rem,':');
[sec,rem]=strtok(rem,'.');
sec = regexprep(sec,':','');
[msec,rem]= strtok(rem,' ');
[msec,y] = strtok(msec,'.');
if(strcmp(rem,' PM'))
hours = str2num(hours);
hours = hours+12;
hours = num2str(hours);
end
totaltime = [year date month hours mins sec msec]

Weitere Antworten (1)

Walter Roberson
Walter Roberson am 27 Mär. 2014
datestr(datevec('03/06/2014 11:39:04.324 PM', 'MM/DD/YYYY hh:mm:ss.fff PM'), 'YYYYMMDDhhmmssfff')
  2 Kommentare
Chandrasekhar
Chandrasekhar am 27 Mär. 2014
so simple..
Walter Roberson
Walter Roberson am 27 Mär. 2014
You could also use datenum instead of datevec but I think datevec should be more resistant to round-off.

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