How can i get a pathname with \*.jpg for an image folder.

I am using

1.  folder_name = uigetdir('C:\Users\Student\Documents\MATLAB\matlab program folder')

2.  dirNamev =('C:\Users\Student\Documents\MATLAB\matlab program folder\9.15\*.jpg');
    filesv = dir(dirNamev);

to get the folder name, but form 1---> it gives me only "C:\Users\Student\Documents\MATLAB\matlab program folder\9.15". 9.15 is a folder containing set of 11 images. My aim is to get a 11x1 struct as in --->form 2. I want to go for 1st method because the folder may change every time and user may need to make a change. Please help me with some ideas.

Answer 1

[Jan]

folder_name = uigetdir('C:\Users\Student\Documents\MATLAB\matlab program folder');
filesv = dir(fullfile(folder_name, '*.jpg'));

[Nithya]

I got the files with this command.But i also require the pathname with file separator at the end to pass to function and i am nt able to get that. Is there a solution for that. i get this for folder name:

'C:\Users\Student\Documents\MATLAB\matlab program folder\9.15'

but can i get through some other command:

'C:\Users\Student\Documents\MATLAB\matlab program folder\9.15\'

[Marta Salas]

you can concatenate the character '\':

   folder_name = [folder_name '\'];

or you can do:

    fullfile(folder_name, filesv(1).name)

Answer 2

[Chandrasekhar]

[fname, pname] = uigetfile({'*.jpg','*.jpeg'})