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HOW TO READ SPECIAL CHARACTERS IN A SINGLE ARRAY

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sonam s
sonam s on 14 Mar 2014
Edited: Walter Roberson on 15 Mar 2014
a1=('a':'z');
b1=('A':'Z');
c1=('0':'9')
IN the above commands a1 contains a to z, and b1 contains A to Z, *c1 contains 0 to 9.
in the similar way how to read special characters like , . ! @ # $ % ^ & * ( ) _ in a single array

Answers (2)

Benjamin Avants
Benjamin Avants on 14 Mar 2014
If you look up the ascii values of the characters you're looking for, you can make an array of those values and then cast it to char
Example:
d1 = 1:33;
d1 = char(d1);
  3 Comments
Benjamin Avants
Benjamin Avants on 14 Mar 2014
1:33 was just an example. You'll need to look up the actual ascii character values online. I would suggest a google search for "ascii table". I think most of the characters in the 1:33 range are special characters, not symbols. Try the range 33:47 for a few of the printable characters.

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Walter Roberson
Walter Roberson on 14 Mar 2014
Edited: Walter Roberson on 15 Mar 2014
char([33:47, 58:64, 91:96, 123:126])
after that one gets into the non-ASCII characters such as '©'.
Another way of expressing this is:
d1 = union(union(a1, b1), c1);
d2 = setdiff(' '+1:127, d1);
Note: earlier I had setintersect() instead of setdiff()

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