Hi! I would like to create a conditional statement where the parameters of my if statement is changing. Is it possible to vary the parameters in the if statement?
Here is an example:
x10=1;
i=10;
word='x';
if ('%s%d~=1',word,i)
v='not working'
end
I tried this one but it is not working, any suggestion on how to make it work?

 Akzeptierte Antwort

the cyclist
the cyclist am 9 Mär. 2014

1 Stimme

Here is the closest I can get to the code that I think you wanted:
x10=1;
i=10;
word='x';
% Create a "pass/fail" variable that will be tested.
eval(sprintf('PF = %s%d~=1;',word,i))
% Do the test
if PF
v = 'not working'
end

3 Kommentare

Guessing you can avoid some of this awkward code by using cell array variables such as
x{10}
rather than names like x10, but maybe not, because it looks like even the text of the variable name can vary.
ericson
ericson am 9 Mär. 2014
Yes, both the variable and digit vary
Is there an alternative way wherein I don't need to store it to another variable? I'm using this code for my GUI wherein I will need that code to compare to almost 3000 variables. If I add more variables, it will make the real time clock in my GUI hang.
x10=1;
i=10;
word='x';
% Create a "pass/fail" variable that will be tested.
eval(sprintf('if %s%d~=1, v = ''not working''; disp(v); end ',word,i))
If you don't actually need to display the 'not working' text, then you can get rid of the
disp(v)
statement inside the eval() statement.

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Mischa Kim
Mischa Kim am 9 Mär. 2014
Bearbeitet: Mischa Kim am 9 Mär. 2014

0 Stimmen

Something like:
mynum = 2; % change to mynum = 1
x10 = 1;
word = 'x';
i = 10;
if (eval(genvarname(strcat(word,num2str(i)))) == mynum)
fprintf('x10 is %d\n', mynum);
else
fprintf('x10 is not %d\n', mynum);
end

1 Kommentar

ericson
ericson am 9 Mär. 2014
Is there an alternative way wherein I don't need to store it to another variable? I'm using this code for my GUI wherein I will need that code to compare to almost 3000 variables. If I add more variables, it will make the real time clock in my GUI hang.

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