Info

Diese Frage ist geschlossen. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.

Complex question: How to find a formula's unique values when plotted with other formulae?

4 Ansichten (letzte 30 Tage)
A
A am 7 Mär. 2014
Geschlossen: MATLAB Answer Bot am 20 Aug. 2021
Hi everyone,
I'm neither a matlab expert nor a mathematician. I have more than 2 complex surface plots based on equations that resemble z = x + 2y.
Imagine I have three equations like so:
z = x + 2y; z = 2x + 2y; z = 3x + 2y;
Is there a way to find out [x,y,z] values or range of values where each formula deviates from others? I am trying to find out values or range of values which are unique to each formula and not 'had' by other formulas?
Does this make sense? I can clarify further if needed.
All I am trying to do is figure out x and y Values that are unique to each formula.
Thank you

Antworten (3)

David Sanchez
David Sanchez am 7 Mär. 2014
You can see it graphically with this code:
x=-10:.1:10;
y=-10:.1:10;
[xx yy] = meshgrid(x,y);
z1 = xx + 2.*yy;
z2 = 2.*xx + 2.*yy;
z3 = 3.*xx + 2.*yy;
surf(xx,yy,z1)
hold on
surf(xx,yy,z2)
surf(xx,yy,z3)
hold off
xlabel('xx')
ylabel('yy')
zlabel('Zs')

A
A am 7 Mär. 2014
Thank you for that. Can I see it non-graphically?

A
A am 7 Mär. 2014
Also, that is not quite what I wanted. That seems to be simply graphing the surface plots. What I want to see is the 'delta'. For example, I want the graph to show me only unique values for each formula.
When you have three equations, there are certain values which are 'shared' between all three equations. There are certain values which are not 'shared' or are unique values for each of the three equation. I want to see those unique values for each formula in surface form and in a form which simply lists all those unique values?
Thank you and I am sorry for having such a difficult request. I hope there is an answer for this.

Diese Frage ist geschlossen.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by