area, stairs

33 Ansichten (letzte 30 Tage)
Hamed Amini
Hamed Amini am 20 Jul. 2011
Bearbeitet: Bill Tubbs am 30 Mär. 2024 um 18:47
Is there any property setting for 'area' function which generates the 'straits' for the boundary of the colored regions instead of 'plot' curves?

Akzeptierte Antwort

Oleg Komarov
Oleg Komarov am 20 Jul. 2011
% Random row input
x = 1:10;
y = rand(1,10);
% Normal area chart
subplot(3,1,1)
area(x,y)
% Stairs chart (non area)
subplot(3,1,2)
stairs(x,y)
% Stairs area
subplot(3,1,3)
x = [x;x];
y = [y;y];
area(x([2:end end]),y(1:end))
  1 Kommentar
Hamed Amini
Hamed Amini am 20 Jul. 2011
Very Clever! Thanks Oleg.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Bill Tubbs
Bill Tubbs am 30 Mär. 2024 um 4:33
Bearbeitet: Bill Tubbs am 30 Mär. 2024 um 18:47
Building on Oleg's answer I wrote a function for doing the same thing with a stacked area plot. However, the data in the x and Y arguments here are aligned vertically in the rows, not horizontally in the columns.
function area_step_plot(x, Y)
assert(size(x, 2) == 1)
nx = size(x, 1);
Y = Y(1:nx-1, :); % final y-values are not used
ny = size(Y, 2);
X = [x x]';
X2 = X(2:end-1)';
Y2 = reshape(permute(cat(3, Y, Y), [3 1 2]), [], ny);
area(X2, Y2)
end
The Y argument can be a matrix of column vectors containing different data series.
x = (1:10)';
Y = rand(10, 3); % Note: last row is not plotted
area_step_plot(x, Y)

Kategorien

Mehr zu Line Plots finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by