for i = 1:19
P(i) = [2.8*10^-4:0.1*10^-4:4.2*10^-4]
I cannot figure out how to fix my loop

3 Kommentare

Jacob
Jacob am 25 Feb. 2014
for i = 1:15*****
dpb
dpb am 26 Feb. 2014
From what you're showing, you don't need (or want) a loop at all.
doc colon
and read the "Getting Started" section in help on manipulating arrays in Matlab to begin to get the picture.
per isakson
per isakson am 26 Feb. 2014
P = [2.8e-4:1e-5:4.2e-4];
and
P = [2.8*10^-4:0.1*10^-4:4.2*10^-4];
return identical results.

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Rick Rosson
Rick Rosson am 26 Feb. 2014
Bearbeitet: Rick Rosson am 26 Feb. 2014

0 Stimmen

No need for a for loop, no need for square brackets. Also, might as well pull common scale factor out using distributive property:
P = (2.8:0.1:4.2)*1e-4;

1 Kommentar

Jacob
Jacob am 26 Feb. 2014
Thanks for your help, but I apologize I did not put the entire code on the question yesterday.
for i = 1:15
P = 2.8e-4:.1e-4:4.2e-4; ???
Kw(i) = 10^-14;
Kh(i) = 10^-1.46;
Ka1(i) = 10^-6.3;
Ka2(i) = 10^-10.3;
func(i) = @(ph,P)Kw/(10^-ph)+(Ka1*Kh*P)/(10^-ph)+(2*Ka1*Ka2*Kh*P)/(10^-ph)^2-(10^-ph);
ph(i) =7;
xl(i) = -20;
xu(i) = 20;
es(i) = 0.1;
[ phout(i), iter(i) ] = bisect( func,xl,xu,es,P )
end

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