Regarding Interpolation( vertical)
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I have two data sets in which one is 4D data sets and another one is 2D.
1) first data: 120( longitude) x 90(latitude) x 34 (vertical level) x 8 (Time) 2) second data: 15( vertical level) x 469( number of observations)
I would like to interpolate 34 vertical levels to 15 vertical levels. so somebody knows how to fix this problem?
Antworten (2)
Sean de Wolski
am 18 Jul. 2011
A = rand(5,5,34,5);
[ii jj kknew LL] = ndgrid(1:5,1:5,linspace(1,34,15),1:5);
C = interpn(A,ii,jj,kknew,LL);
You could just use interpn directly, thought this will use information from other dimensions.
4 Kommentare
Uday
am 18 Jul. 2011
Sean de Wolski
am 18 Jul. 2011
I just did that as an example since I didn't want to kill the RAM on my laptop. For your case:
[ii jj kknew LL] = ndgrid(1:120,1:90,linspace(1,34,15),1:8);
C = interpn(A,ii,jj,kknew,LL);
Also, how do you plane on comparing a 2d matrix 15x469, to a 4d matrix? I think bsxfun/repmat might be necessary. Or do you want to append it?
I.e.
cat(3,A,C)? (in which case you don't even need to interpolate down?
Please clarify the goal.
Uday
am 19 Jul. 2011
Sean de Wolski
am 19 Jul. 2011
Show us _exactly_ what you wrote.
Andrei Bobrov
am 18 Jul. 2011
In = DataInput; % Array 4D
[a b oldc d] = size(In);
newc = 15;
Out = zeros([a b newc d]);
for j4 = 1:d
d1 = reshape(permute(In(:,:,:,j4),[3 2 1]),oldc,[]);
Out(:,:,:,j4) = permute(reshape(cell2mat(arrayfun(@(i1)interp1((1:oldc)',d1(:,i1),linspace(1,oldc,newc)'),1:a*b,'un',0)),newc,b,a),[3 2 1]);
end
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