What's the difference between code?

It's a stupid question but these two line of code do the same thing wthere dt1 is a constant. Is it right?

    prova= sum((out1.Y{i}(:,3:end)).^2)*dt1;

h=1;
for i=3:end;
y1=out.Y(:,i);   
prova(h)=sum(y1.^2)*dt1;    
h=h+1;
end;

[Jan]

Replace for i=3:end by for i = 3:size(out.Y, 2) .

Answer 1

[Walter Roberson]

Yes, they appear to be, at least to the limits of round-off error.

[Francesco]

Ok ok. I just wanted a confirmation.