How can I calculate the difference in time (seconds) with datetime?
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Diego
am 13 Feb. 2014
Kommentiert: Steven Lord
am 13 Apr. 2021
I have to read a csv file. A column of this file has the next format:
2014/01/16 13:12:12.
Thanks for the help of Mischa Kim I have achieved to read in this format, so this not a problem.
So that my goal is to represent in X axis the time in seconds and Y axis the RSSI related to each second because as you can said me the problem if I represented the TIME_STAMP in the format 13:13:12 there're too many labels If I print all of them.
The First value of TIME_STAMP is 13:12:12 that corresponds to second 1. The Second Value of TIME_STAMP is 13:12:13 that corresponds to second 2. Until the last value...
If you don't understand my question tell me and I'll try to explain better!
Dou you Know a function or a way to calculate the TIME_STAMP in seconds with the aim to represent in x axis the time in seconds with each value.
I attach the csv file.
I would be grateful If you Know how can I do this! Thanks Mischa for your time! Greetings.
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Mischa Kim
am 13 Feb. 2014
If you are starting with date strings, use datenum to convert dates into number (= days) format. As an example:
d2s = 24*3600; % convert from days to seconds
d1 = d2s*datenum('13:12:12');
d2 = d2s*datenum('13:12:16');
display(d2-d1)
So simply loop through the date strings and subtract the first value.
Of course, if you already have dates in double format you would just do subtraction without conversion. It gets even simpler if you know that you have consistent 1 sec spacing between data points. You then just simply
tspan = 1:1:num_datapoints
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Jos (10584)
am 17 Feb. 2014
You can also use the dedicated function ETIME (with DATEVEC)
date1 = '2014/01/16 13:12:12'
date2 = '2014/01/16 13:12:13' % one second later
etime(datevec(date2),datevec(date1))
If you have a list of date/times
DT = {'2014/01/16 13:12:13' '2014/01/16 13:12:15' '2014/01/16 13:13:13' '2014/01/17 13:12:13' }
reftime = DT{1} ;
etime(datevec(DT), repmat(datevec(reftime),numel(DT),1))
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João Campos
am 13 Apr. 2021
It worked for me, but I am losing my miliseconds information :(, does anybody knows how to fix that?
Steven Lord
am 13 Apr. 2021
In the years since the original answer for this question we introduced the datetime array that you should use instead of converting to datenum values.
dt = datetime('now')
dt2 = dt + seconds(1.2345)
s = seconds(dt2-dt)
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