How “size(x,3)>1” works on an image?

4 Ansichten (letzte 30 Tage)
Shaila parvin
Shaila parvin am 11 Feb. 2014
Beantwortet: Image Analyst am 11 Feb. 2014
x=imread('a.jpg');
if (size(x,3)>1)%if RGB image make gray scale
try
x=rgb2gray(x);%image toolbox dependent
catch
x=sum(double(x),3)/3;%if no image toolbox do simple sum
end
end
I don’t understand the if condition. How “size(x,3)>1” works on an image? Can anyone please help me?

Akzeptierte Antwort

Thomas
Thomas am 11 Feb. 2014
size(x,3) - if it is greater than 1 than it is a color RGB image.
try size(x) and see - if you get two dimensions its grayscale if you get three dimensions its RGB and that is exactly what your code is looking for ( if its color RGB convert to grayscale)

Weitere Antworten (1)

Image Analyst
Image Analyst am 11 Feb. 2014
I prefer the more explicit:
% Get the dimensions of the image.
% numberOfColorBands should be = 1 or 3 depending if image is grayscale or RGB.
[rows, columns, numberOfColorBands] = size(grayImage);
if numberOfColorBands > 1
% It's not really gray scale like we expected - it's color.
% Convert it to gray scale by taking only the green channel.
grayImage = grayImage(:, :, 2); % Take green channel.
end
Here is how to check if you have the Image Processing Toolbox installed:
% Check that user has the Image Processing Toolbox installed.
hasIPT = license('test', 'image_toolbox');
if ~hasIPT
% User does not have the toolbox installed.
message = sprintf('Sorry, but you do not seem to have the Image Processing Toolbox.\nDo you want to try to continue anyway?');
reply = questdlg(message, 'Toolbox missing', 'Yes', 'No', 'Yes');
if strcmpi(reply, 'No')
% User said No, so exit.
return;
end
end

Kategorien

Mehr zu Image Processing Toolbox finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by