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Cannot get factorial loop to work! Do not know command...

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S
S am 9 Feb. 2014
Beantwortet: Roger Stafford am 9 Feb. 2014
The question is evaluate the following series: 1^2 + 2^2 +3^2 ... + 100^2. The answer is suppose to be 338350 but the only code i can get working is
a=[1:100] b=2; y=a.^b for y=1:length(a) end
which gives me each columns value, but does not add it up to value 338350! I have tried everything for a whole week please help :(

Antworten (2)

Mischa Kim
Mischa Kim am 9 Feb. 2014
Bearbeitet: Mischa Kim am 9 Feb. 2014
Use
a = [1:100];
b = 2;
y = 0;
for ii = 1:length(a)
y = y + a(ii)^b;
end
display(y);
Your sum, y, needs to be inside the loop to be updated. Alternatively, you can make use of MATLAB's matrix operations
y = sum([1:100].^2);
  3 Kommentare
John D'Errico
John D'Errico am 9 Feb. 2014
Bearbeitet: John D'Errico am 9 Feb. 2014
Noe that the internal brackets [] are slightly bad, in the sense that they may make your code slightly less efficient. Use () there instead, so
y = sum((1:100).^2);
is better. Not a major issue, but one to remember. If you don't really need brackets, which will result in an extra function call overhead that was never needed, don't use them. Use parens instead. I'm pretty sure that mlint flags this issue.
John D'Errico
John D'Errico am 9 Feb. 2014
Another option here would be
y = dot(1:100,1:100);

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Roger Stafford
Roger Stafford am 9 Feb. 2014
Yet another way is:
n = 100;
y = n*(n+1)*(2*n+1)/6;

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