How to choose a column where the min of the first row is

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Reuben
Reuben am 9 Feb. 2014
Kommentiert: Reuben am 9 Feb. 2014
Hello! I am new to Matlab and having a tough time doing the following. I have a set of distances computed for each respective time.
where all the list of distances is stored as 'd' and each RESPECTIVE time these distances occur at is 't'
I made a matrix A = [d;t]. Essentially...I want to find out the respective time value when d is minimum.
I tried to pick out the row as
>> A(2,min(d)). Obviously I see now how that doesn't work since its the column number and not for that value.
Is there anyway matlab can recognize which column number that min(d) exists...and then display the WHOLE column so i can also see the respective time value it exists at. Thanks!
FOR EXAMPLE:
a = [ 5 4 1 3 ] b = [ 1 2 3 4 ]
H = [a;b]
I want to display the column [1;3] since min(a) exists in this column. I need to keep each b value tied to each a however.

Akzeptierte Antwort

Mischa Kim
Mischa Kim am 9 Feb. 2014
Bearbeitet: Mischa Kim am 9 Feb. 2014
Use
G = H(:,a==min(a))
or, the more general approach avoiding reference to a,
G = H(:,H(1,:)==min(H(1,:)))

Weitere Antworten (1)

Azzi Abdelmalek
Azzi Abdelmalek am 9 Feb. 2014
a = [ 5 4 1 3 ]
b = [ 1 2 3 4 ]
[mina,idx]=min(a);
your_column=[mina;b(idx)]

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