Generating a HSV Histogram without For-loops
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Gareth
am 6 Feb. 2014
Kommentiert: Gareth
am 6 Feb. 2014
Hi,
I'm creating a video processing tool in MatLab, which works, but my code is extremely slow, which I believe is due to my use of for-loops.
One example of this is in creating a HSV Histogram for a video. The code I have is as follows:
function [hsvHist] = generateHSVHist(hsvVid, numRows, numColumns, numFrames)
H = zeros(12,1);
S = zeros(4,1);
V = zeros(4,1);
for frame = 1 : numFrames
for row = 1 : numRows
for column = 1 : numColumns
h = hsvVid(row,column,1,frame);
s = hsvVid(row,column,2,frame);
v = hsvVid(row,column,3,frame);
idxH = ceil(h*12);
idxS = ceil(s*4);
idxV = ceil(v*4);
%ensure no zero indices
if idxH == 0
idxH = 1;
end
if idxS == 0
idxS = 1;
end
if idxV == 0
idxV = 1;
end
H(idxH) = H(idxH)+1;
S(idxS) = S(idxS)+1;
V(idxV) = V(idxV)+1;
end
end
end
%Normalise the histograms
totalPixels = numFrames * numRows * numColumns;
H = H/totalPixels;
S = S/totalPixels;
V = V/totalPixels;
%Concatenate the histograms
hsvHist = [H;S;V];
end
Do you guys have any tips or advice on how I can approach this problem without using for-loops? Any help is greatly appreciated.
Thanks,
Gareth
0 Kommentare
Akzeptierte Antwort
Walter Roberson
am 6 Feb. 2014
No loop needed.
h = hsvVid(:,:,1,frame);
idxH = max(1, ceil(h*12));
H = histc(idxH(:), 1:12);
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Histograms finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!