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Can you help me solving that?

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Rengin
Rengin am 30 Jan. 2014
Bearbeitet: Walter Roberson am 30 Jan. 2014
A=[1 2 3 4 5 6 7 8 9 10]
B=[a b c d e f ]
I want to create such a matrix as a result:
C[1+a 1+b 1+c 1+d 1+e 1+f ; 2+a ... 2+f ; 3+a... 3+f; ......;10+a...10+f]
A is 1x10 and B is 1x6 sized matrices. C is 10x6 sized matrix.
Thank you for your help!

Akzeptierte Antwort

Mischa Kim
Mischa Kim am 30 Jan. 2014
How about:
A = [1 2 3 4 5 6];
b = [1 2 3];
C = zeros(size(A'*b));
for ii = 1:length(A)
C(ii,:) = b + A(ii);
end

Weitere Antworten (2)

Iain
Iain am 30 Jan. 2014
Bearbeitet: Iain am 30 Jan. 2014
C = A * B'; % will give you a 1x1.
C = (A' * B)'; will give you a 10x6.
C = A'*B; will give you a 6 x 10.
  2 Kommentare
Rengin
Rengin am 30 Jan. 2014
Yes you are right but the thing is that I am getting the first element of A matrix (which is "1" ) and adding it the first row of the B matrix and getting the first row of C matrix (1+a 1+b 1+c 1+d 1+e 1+f). I am doing that procedure untill fulfill all of my rows (I have 6 rows)... I know how to multiply the matrices. My guestion is how to create a new matrix according to my specific summary rule.
Jos (10584)
Jos (10584) am 30 Jan. 2014
you mean: I have 10 rows ...

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Jos (10584)
Jos (10584) am 30 Jan. 2014
No need for an explicit loop as you can exploit the power of MatLab with BSXFUN.
% example data
A =[1 2 3 4 5 6 7 8 9 10]
B =[100 200 300 400 500]
% engine
C = bsxfun(@plus, A(:), B)

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