change values in a matrix

I have a big matrix and I want to correct it The first column I want to remove those -1 and -2 from my data

for example my data is as follows

   0,206470489501953  -1,86300277709961  -2,64120101928711
  0,270366668701172  -1,92737579345703  -2,63929367065430
  0,382900238037109  -1,87778472900391  -2,54106521606445
  0,349044799804687  -1,72615051269531  -2,34174728393555
  0,287532806396484  -1,63698196411133  -2,47240066528320

I want to have it as follows

 0,206470489501953  0,86300277709961  0,64120101928711
  0,270366668701172  0,92737579345703  0,63929367065430
  0,382900238037109  0,87778472900391  0,54106521606445
  0,349044799804687  0,72615051269531  0,34174728393555
  0,287532806396484  0,63698196411133  0,47240066528320

nothing changed , I just removed the minus 1 and minus 2 from my data

Unfortunately, I cannot use abs function since I have also big numbers in my data that i cannot touch like follows;

46,5722084045410  110,708236694336  3,10182571411133
44,4703102111816  108,825206756592  4,81796264648438
42,4933433532715  106,929779052734  6,19792938232422
40,4911041259766  104,907035827637  6,72531127929688

 I only need to remove those -1, -2, -3 from my data but not changing the positive values with higher than 1 like above

[Jos (10584)]

The presence of commas suggests that this is a text (character, string) matrix rather than a numerical matrix … Is that the case and is is what you really want?

[Niki]

Not really, this is not a text mining, it is values,

[Jos (10584)]

Usually values contain decimal dots ...

[Niki]

you are right, however thanks

Answer 1

[Jos (10584)]

Another problem needs another solution:

a = [0.1234 -1.9876 -2.0001 22.9999]
b = a              % work on a copy
q = fix(b)<0 
b(q) = abs(rem(b(q),1))

Answer 2

[Mischa Kim]

Use the rem command:

A = [0.1 -2.3]
A =
   0.100000000000000  -2.300000000000000
abs(rem(A,1))
ans =
   0.100000000000000  0.300000000000000

[Niki]

Thanks but I cannot use the abs function, I explain more in the text

[Azzi Abdelmalek]

Then use

idx=A<=-1
A(idx)=rem(A(idx),1)

Answer 3

[Azzi Abdelmalek]

idx=A<=-1
A(idx)=A(idx)-fix(A(idx))

[Niki]

Thanks but I cannot use the abs function, I explain more in the above text (question)

Answer 4

[Jos (10584)]

For numerical arrays use REM and ABS. An example:

a = [0.1234 -1.9876 -2.0001]
b = abs(rem(a,1))
% [0.1234 0.9876 0.0001] as required

[Niki]

Thanks but I cannot use the abs function, I explain more in the text