how to sort a dataset into different group and get sum of each group?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Genhou
am 23 Jan. 2014
Beantwortet: Walter Roberson
am 24 Jan. 2014
Hi everyone,
Now I have a question on how to sort a dataset into different group and get sum of each group, which tortures me for sevral day. I hope to get help from you, and thanks.
An example of my dataset is shown below. There are 9 rows and 12 columns. This first and second rows are x, y coordinates and the third row is the correponding value of each (x ,y).
-1.986 -2.648 -3.310 -3.972 -4.634 -5.296 -5.958 -6.621 -7.283 -7.945 -8.607 -9.269 -9.931 -10.593 -11.255 -11.917 -12.579//
-4.515 -6.020 -7.525 -9.030 -10.536 -12.041 -13.546 -15.051 -16.556 -18.061 -19.566 -21.071 -22.576 -24.081 -25.586 -27.091//
0.002 0.003 0.003 0.004 0.004 0.005 0.005 0.005 0.006 0.006 0.006 0.007 0.007 0.007 0.007 0.008 0.008 0.008
-3.967 -5.289 -6.611 -7.934 -9.256 -10.578 -11.900 -13.223 -14.545 -15.867 -17.189 -18.512 -19.834 -21.156 -22.478 -23.801//
-5.372 -7.163 -8.954 -10.745 -12.536 -14.326 -16.117 -17.908 -19.699 -21.490 -23.280 -25.071 -26.862 -28.653 -30.443 -32.234//
0.001 0.002 0.002 0.003 0.003 0.003 0.004 0.004 0.004 0.005 0.005 0.005 0.005 0.005 0.005 0.006
-3.606 -4.808 -6.011 -7.213 -8.415 -9.617 -10.819 -12.021 -13.223 -14.425 -15.627 -16.829 -18.032 -19.234 -20.436 -21.638//
-2.758 -3.678 -4.597 -5.517 -6.436 -7.356 -8.275 -9.195 -10.114 -11.034 -11.953 -12.873 -13.792 -14.711 -15.631 -16.550//
0.002 0.003 0.003 0.004 0.005 0.005 0.006 0.006 0.006 0.007 0.007 0.007 0.008 0.008 0.008 0.008
I want to sort the data according to (x,y) coordinates into idfferent groups and get the sums of each group. In this case, the group can be
(-35<x<-30,-35<y<-30),(-30<x<-25,-35<y<-30),....(-5<x<0,-35<y<-30);
(-35<x<-30,-30<y<-25),(-30<x<-25,-30<y<-25),....(-5<x<0,-30<y<-25);
(-35<x<-30,-25<y<-20),(-30<x<-25,-25<y<-20),....(-5<x<0,-25<y<-20);
(-35<x<-30,-5<y< 0),(-30<x<-25,-5<y< 0),....(-5<x<0,-5<y<0)
Then get the sum of each group.
Thanks once again.
2 Kommentare
Walter Roberson
am 23 Jan. 2014
Is it correct that you are wanting to distribute into a rectangular grid? If so it becomes easy. Even easier if the grid boundaries are the same distance apart.
What should be done for the case that x is exactly 30? As you have used inequalities at each stage, points on the boundaries have no-where to go.
Akzeptierte Antwort
Walter Roberson
am 24 Jan. 2014
mingrid = -30;
gridgap = 5;
xgrididx = 1 + floor((x - mingrid) ./ gridgap);
ygrididx = 1 + floor((y - mingrid) ./ gridgap);
gridcounts = accumarray( [xgrididx(:), ygrididx(:)], 1 );
Now gridcounts is an array of counts.
row K is the range (K - 1) * gridgap + mingrid <= x < K * gridgap + mingrid . Same calculation for column number and y.
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Shifting and Sorting Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!