replacing ascending numbers with continous numbers
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Hello everybody,
I am looking for a fast and efficient way to convert a vector of non continous ascending numbers to continous numbers.
As an example:
The vector
[4 20 35 22 10 49]
should become
[1 3 5 4 2 6]
at the moment I'm using a for loop, look for the lowest number write the runtime index into the result vector and set the position in the original vector to an illegal value. I know this is not the best way but it was the only one I could think of.
Also I'm not doing a single vector at a time but doing this to the columns of a matrix.
Thank you
0 Kommentare
Akzeptierte Antwort
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Logical finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!