error with results, matlab
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Monika
am 21 Jan. 2014
Kommentiert: Monika
am 22 Jan. 2014
Where is error? My program showed my only WYKRYTO, but I don't know what.
fprintf('\nWYKRYTO: ');
if (kaszel == max([kaszel, smiech, krzyk, chrzakanie]))
fprintf('kaszel');
elseif (smiech == max([kaszel, smiech, krzyk, chrzakanie]))
fprintf('smiech');
elseif (krzyk == max([kaszel, smiech, krzyk, chrzakanie]))
fprintf('krzyk');
elseif (chrzakanie == max([kaszel, smiech, krzyk, chrzakanie]))
fprintf('chrzakanie');
end
13 Kommentare
Akzeptierte Antwort
Walter Roberson
am 21 Jan. 2014
max([array1, array2])
means
max(horzcat(array1, array2))
which in turn means
max(horzcat(array1, array2), [], 1)
which will calculate the column-by-column maximum of horzcat(array1, array2), which is going to give you a result which is 1 x (size(array1,2) + size(array2,2)) .
And then you try to compare the entire array array1 to the result of the max(), so you are comparing
size(array1,1) x size(array1,2)
to
1 x (size(array1,2) + size(array2,2))
and you can see by examination that the only way that can work is if array1 only has a single row and array2 is empty. (Well, that case would be treated differently by MATLAB, but you would still end up with mismatched lengths for the comparison)
Taking into account that you have entire arrays to be compared, what do you want your output to be? A 2D cell array of strings that indicates at each location which of the four arrays was the maximum at that point ? Or do you wish to know which of the four has the greatest average magnitude? Or something else?
9 Kommentare
Weitere Antworten (2)
per isakson
am 21 Jan. 2014
2 Kommentare
Matt J
am 21 Jan. 2014
Hard to imagine that applies to max() operations. I'm not encountering issues, at least.
per isakson
am 22 Jan. 2014
Bearbeitet: per isakson
am 22 Jan. 2014
Agree, but it's a good habit not to use "==" with floats.
Siehe auch
Kategorien
Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!