C=[ ];
for A=1:4
B=[5 10 5 10];
end
C=[A,B]
for example :
A=1:4
and
B=[5 10 5 10]
if A==1 & 3 then B==5, and when A==2&4 B==10
A B
1 5
2 10
3 5
4 10
How we could use Matlab code to obtain the above loop as shown in the picture, Thank you in advance for your assistance,

 Akzeptierte Antwort

Amit
Amit am 18 Jan. 2014
Bearbeitet: Amit am 18 Jan. 2014

0 Stimmen

I think simple doing
C = [A' B'];
would work. You dont need to do this in a loop.

5 Kommentare

UTS
UTS am 18 Jan. 2014
Bearbeitet: UTS am 18 Jan. 2014
WOW, Thank you for your prompt reply. However, I got error as:
Error using horzcat Dimensions of matrices being concatenated are not consistent.
Error in checkthis (line 8) C = [A' B']
Amit
Amit am 18 Jan. 2014
Well in simple terms, in [X Y], both X and Y should be column matrix (nx1) When I wrote [A' B'], I assumed both A and B being row vector as A = 1:4, create a row matrix and B = [5 10 5 10] creates a row matrix. If this changed any how in your code, you have to modify C = [A' B'] accordingly.
Do me a favor and post the result for size(A) and size(B) before you do C = [A' B']
UTS
UTS am 18 Jan. 2014
Thank you very much, I tried to do this
B=[5 10 5 10];
A=[]; C=[B,A]
for A=1:4
B=[5 10 5 10];
size(A);
size(B) ;
C=[A';B']
end
The answer as:
C =
1
5
10
5
10
C =
2
5
10
5
10
C =
3
5
10
5
10
C =
4
5
10
5
10
Amit
Amit am 18 Jan. 2014
Bearbeitet: Amit am 18 Jan. 2014
Okay, that's the problem.
What I said was to do is:
B = [5,10,5,10];
A = 1:4;
C = [A' B'];
Than simple. No loops, nothing.
UTS
UTS am 18 Jan. 2014
Thank you very much C =
1 5
2 10
3 5
4 10

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am 18 Jan. 2014

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am 18 Jan. 2014

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