Wavelet and image processing

2 Ansichten (letzte 30 Tage)
Ayesha
Ayesha am 17 Jan. 2014
Kommentiert: Walter Roberson am 24 Jan. 2017
Hi there!
Alright, so I've been working on this little piece of code to approximate image using wavelets and there's this error I'm getting:
Subscripted assignment dimension mismatch.
So the code goes this way:
I = imread('lena.png');
J = perform_wavelet_transf(I,j0,+1);
n = size(I,1);
J1 = zeros(n);
J1(1:n/4,1:n/4) = J(1:m,1:m);
result = perform_wavelet_transf(J1,j0,-1);
imshow(result,[]);
I've been wondering since hours on what could possibly go wrong with this piece and I guess somethings not right with
J1(1:n/4,1:n/4) = J(1:m,1:m);
What do you think?
And yes, Thanks alot!!! for your help in advance :)
  2 Kommentare
Walter Roberson
Walter Roberson am 17 Jan. 2014
Which line is the error occurring on?
Ayesha
Ayesha am 17 Jan. 2014
The fifth line:
J1(1:n/4,1:n/4) = J(1:m,1:m);

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Walter Roberson
Walter Roberson am 17 Jan. 2014
You have not shown us how you construct "m" so all we can do is hypothesize that you construct it without regard for the actual size of lena.png
  2 Kommentare
Ayesha
Ayesha am 17 Jan. 2014
That's the part I'm experimenting since wavelets deals with coarse details and hence j0 is an integer.
j0=128;
M = 2^(-j0);
m=sqrt(M);
Walter Roberson
Walter Roberson am 24 Jan. 2017
sqrt(2^-128) is 2^-64, which is a number less than 1. 1:m would then be the empty range, so J(1:m,1:m) would be empty. You are trying to store that empty range into a non-empty location.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu AI for Signals and Images finden Sie in Help Center und File Exchange

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by