Symbolic Differentiation wrt time

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zoom am 22 Dez. 2013
Kommentiert: Walter Roberson am 1 Apr. 2014
I have such an expression;
(x(t) + y(t))^2
Where x and y are function of t How can I symbolically take the derivative of this expression with respect to t
Which has to result in 2[xx' + xy' + yx' + yy']

Antworten (1)

Wayne King
Wayne King am 22 Dez. 2013
syms t x(t) y(t)
diff((x(t)+y(t))^2)
The above gives the output:
2*(x(t) + y(t))*(diff(x(t), t) + diff(y(t), t))
which is equivalent to what you have in your post.
  2 Kommentare
Mohammad
Mohammad am 1 Apr. 2014
hi, what about when we want to have upper degree derivatives of the same expression?
Walter Roberson
Walter Roberson am 1 Apr. 2014
diff((x(t)+y(t))^2,t,3) %third derivative

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