Hi,
I made a 2d matrix with two for loops:
for k = 1:32
for l = 1:32
P_new(l,k) = P_old(l) + (LODF(l,k) * P_old(k));
end
end
P_old is here a 32 x 1 matrix and LODF is a 32 x 32 matrix which is already computed. How can I vectorize this code to avoid the for loops? Thanks in advance.

 Akzeptierte Antwort

Matt J
Matt J am 10 Dez. 2013

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P_new= bsxfun(@times, LODF, P_old.');
P_new= bsxfun(@plus, P_new,P_old);

2 Kommentare

Jip
Jip am 10 Dez. 2013
Bearbeitet: Matt J am 10 Dez. 2013
Although this code avoids the for loops, it is not faster, which is my purpose. Actually the code is much slower. Any other suggestions?
Matt J
Matt J am 10 Dez. 2013
Bearbeitet: Matt J am 10 Dez. 2013
For 32x32 data, I wouldn't be surprised if the for-loop was the fastest approach. For larger sizes, however, the vectorized approach will start to show superior performance, e.g.,
N=3200;
LODF=rand(N); P_old=rand(N,1);
tic;
P_new=zeros(size(LODF));
for k = 1:N
for l = 1:N
P_new(l,k) = P_old(l) + (LODF(l,k) * P_old(k));
end
end
toc;
%Elapsed time is 0.102201 seconds.
tic;
P_new= bsxfun(@times, LODF, P_old.');
P_new= bsxfun(@plus, P_new,P_old);
toc
%Elapsed time is 0.043591 seconds.
If you're not happy with the speed of your code, you should show us the slow part in its entirety. The small part you've shown is pretty fast, in and of itself.

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Weitere Antworten (2)

Jos (10584)
Jos (10584) am 10 Dez. 2013

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for loops are pretty fast when you use pre-allocation
P_new = zeros(32,32) ;
for k = 1:32
for l = 1:32
P_new(l,k) = P_old(l) + (LODF(l,k) * P_old(k));
end
end
Jip
Jip am 10 Dez. 2013

0 Stimmen

Yes I know, I already did that.

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Jip
am 10 Dez. 2013

Bearbeitet:

am 10 Dez. 2013

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