perl script to matlab code conversion

the following is the program that was converted from perl version to matlab. when executed in perl i got "pa" value around 9.81..but in matlab iam getting only 0.0763..can someone tel me y?..i need this answer badly pls

clc;
clear all;
j=1:6;
for i=0:length(j) 
    beta=2^i;
    alow=0;
    ahigh=10000;
    pa=0;
    r=3;
    eps=0.1;
    gminus=0;
    gplus=0;
    g=0;
    fa=0;
    while((ahigh-alow)>eps)
        pa=(alow+ahigh)/2;
        fa=1-(exp(-((((2^r)-1)/pa)^(beta/2))));
        gminus=(((fa-1)/pa)*(pa-eps))+1;
        glus=(((fa-1)/pa)*(pa+eps))+1;
        fminus=1-(exp(-((((2^r)-1)/(pa-eps))^(beta/2))));
        fplus=1-(exp(-((((2^r)-1)/(pa+eps))^(beta/2))));
        if(((gminus<fminus)&&(gplus>fplus))==1)
            alow=pa;
        else
         ahigh=pa;
      end
         disp(pa)  
    end

[Walter Roberson]

That code would definitely bomb in perl, so you could not have gotten 9.81 when you executed it in perl.

[shobi swaminathan]

I checked in online perl executer..its working

[Simon]

Hi!

It's not so easy to tell where the difference comes from if we only know the matlab code and not the perl code.

BTW, your code is missing an "end" at the end.

[Walter Roberson]

The poster has indicated that this code was executed in perl. Which is not plausible, as perl requires $ or @ before each variable name (except sometimes for file handles.)