Even and Odd parts
92 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Function that gives the even and the odd parts of any given signal
1 Kommentar
Mashhood Saeed
am 18 Nov. 2021
n=-5:5;
yn= 0*(n<0)+1*(n==0)+1*(n>0);
yflip=fliplr(yn);
subplot(3,1,1);
stem(n,yn,'r');
title('plot of yn');
xlabel('time');
ylabel('yn');
ye = (1/2)*(yn+yflip);
subplot(3,1,2);
stem(n,ye,'b');
title('plot of even');
xlabel('time');
ylabel('y even');
yo= (1/2)*(yn-yflip);
subplot(3,1,3);
stem(n,yo);
title('plot of odd');
xlabel('time');
ylabel('y odd');
Antworten (8)
Azzi Abdelmalek
am 18 Nov. 2013
t=-10:10; %vector time
x=rand(1,numel(t)); % Your signal
xmt=[fliplr(x(t>=0)) fliplr(x(t<0))]
xe=0.5*(xmt+x)
xo=0.5*(x-xmt)
subplot(3,1,1);
plot(t,x);
title('Your signal x')
subplot(3,1,2);
plot(t,xe);
title('Even part')
subplot(3,1,3);
plot(t,xo);
title('Odd part')
2 Kommentare
suhaib Dawood
am 23 Sep. 2016
If you have heaviside function what to do to find the even and odd portion ?
JUGAL SUGGALA 17BEC0423
am 30 Aug. 2018
Please can you explain each command or function briefly, how it is working as i am not able to understand the code.
Siddharth Mishra
am 4 Nov. 2019
clc;
clear all;
close all;
x=input("enter the values");
n=0:length(x)-1;
n1=(1-length(x))*0.5:(length(x)-1)*0.5;
y=flip(x);
y
x
x_e=(x+y)*0.5;
x_e
x_o=(x-y)*0.5;
x_o
subplot(311)
stem(n1,x);
title('ACTUAL SIGNAL');
subplot(312)
stem(n1,x_e);
title('EVEN SIGNAL');
subplot(313)
stem(n1,x_o);
title('ODD SIGNAL');
0 Kommentare
Sean de Wolski
am 18 Nov. 2013
signal = rand(1000,1);
even = signal(2:2:end);
odd = signal(1:2:end);
Like this?
1 Kommentar
Sandeep Maurya
am 7 Sep. 2017
n=-10:15; x=[zeros(1,10) ones(1,10) zeros(1,0)]; m=fliplr(n); m1=min([m,n]); m2=max([m,n]); n1=1:length(n); x1=zeros(1,length(m)); x1(n1+nm)=x: x=x1; xe=0.5*(x+fliplr(x)); xo=0.5*(x-fliplr(x)); figure; t=-15:15; subplot(3,1,1);stem(t,x); axis([-15 15 0 1.5]); title('ORIGINAL SIGNAL'); subplot(3,1,2); stem(t,xe); title('Even signal X(n)'); subplot(3,1,3); stem(t,xo); axis([-15 15 -1 1]); xlabel('-----Time-----'); ylabel('--Amplitude--'); title('Odd part of signal');
1 Kommentar
Walter Roberson
am 4 Nov. 2019
The phrase
x1(n1+nm)=x: x=x1
is invalid. It would probably be valid if a semi-colon were used instead of a colon.
Christian Stoddard
am 10 Feb. 2019
myeven = @(x) (1/2)*(myfun(x)+myfun(-x));
myodd = @(x) (1/2)*(myfun(x)-myfun(-x));
0 Kommentare
sushma medabalimi
am 29 Aug. 2019
tmin=-10; dt=0.1; tmax=10;
t=tmin:dt:tmax;
a = 2;
% Generate exponential signal
x1 = exp(a*t);
%Perform time reversal operation
x2 = exp(-a*t);
%Condition to check odd signal
if(x2==x1)
disp('The given signal is even signal')
else if (x2==(-x1))
disp('The given signal is an odd signal')
else
disp('The given signal is neither even nor odd signal')
end
end
0 Kommentare
Kshitiz
am 4 Okt. 2019
clc;
close all;
clear all;
prompt = 'Enter the values';
x=input(prompt)
x_dash=flip(-x);
t1=0:1:length(x)-1;
t1_dash=flip(-t1);
for i=1:length(x)
odd(i)=x_dash(i)/2;
end
for i=2:length(x)
odd(i+length(x))=x(i)/2;
end
odd(length(x))=0;
for i=1:length(x)
t(i)=t1_dash(i);
end
for i=1:length(x)
t(i+length(x))=t1(i);
end
length(t)
length(odd)
subplot(311)
stem(t,odd)
xlim([-10 10])
title('ODD SIGNAL');
x_dash=flip(x);
t1=0:1:length(x)-1;
t1_dash=flip(-t1);
for i=1:length(x)
odd(i)=x_dash(i)/2;
end
for i=1:length(x)
odd(length(x))=x(i)/2;
end
odd(length(x)+1)=x(1);
for i=1:length(x)
t(i)=t1_dash(i);
end
for i=1:length(x)
t(length(x))=t1(i);
end
length(t)
length(odd)
length(odd)
subplot(312)
stem(t,odd)
xlim([-10 10])
title('EVEN SIGNAL');
subplot(313)
stem(t1,x)
xlim([-10 10])
title('ACTUAL SIGNAL')
0 Kommentare
MD asgar
am 18 Jul. 2020
Consider the discrete function x=4*sin(t)+2*cos(t), Write the Matlab code to evaluate the odd even part of Y and plot the subplots in a single plot.
1 Kommentar
Walter Roberson
am 18 Jul. 2020
You should start a new Question for that.
Siehe auch
Kategorien
Mehr zu Denoising and Compression finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!