How can I write the value of the array as an exponent in sprintf
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hello, I want write the following function in the legend of my graph: f(x) = a * x^n.
I calculated a and n. Now I want to replace a and n with the corresponding value and write it as a string. So I want to use the command sprintf:
sprintf('\\rm{f(x) = %0.4g * x^%0.3g}', a, n)
The only problem is that I can't get the value for n as an exponent. How can you do that? Is it possible with sprintf?
Thank you for any help!
0 Kommentare
Akzeptierte Antwort
Matt Fig
am 29 Jun. 2011
Works here:
plot(1:10)
legend(sprintf('f(x) = %0.4g * x^%0.3g', .3, 3))
EDIT In response to comments.
In that case:
legend(sprintf('f(x) = %0.4g * x^{%0.3g}', -.3, -3))
3 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Legend finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!