Subscripted assignment dimension mismatch (size [1 x 1] ~= size [1 x :?])

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want2know
want2know am 7 Nov. 2013
Kommentiert: Azzi Abdelmalek am 7 Nov. 2013
Hi, I wanted to be:
arr(2,1) = arr(2,1) + abs(5.0 minus 5.1);% where I(1,a) is 5.0 and I(1,a+1)is 5.1
Why couldn't I add the below two together? I got this error message: Subscripted assignment dimension mismatch (size [1 x 1] ~= size [1 x :?]).
Function 'MATLAB Function' (#620.435.485), line 23, column 2:
"arr(count,1) = arr(count,1) + abs(I(1,a)-I(1,a+1))"
Launch diagnostic report.
'I' is declared in worskspace as:
I =[5.0000 5.1000 5.2000 5.2000
90.0000 85.0000 80.0000 20.0000]
integ_signal=zeros(5,4);
a=zeros(10);
arr=zeros(5,4);
count=2;
a=1;
arr(count,1) = arr(count,1) + abs(I(1,a)-I(1,a+1));
  7 Kommentare
want2know
want2know am 7 Nov. 2013
May I know what do you mean? I just don't understand why it runs perfectly if I put it in Matlab workspace, however, when it is in Matlab Function Block, i got the above error.
Azzi Abdelmalek
Azzi Abdelmalek am 7 Nov. 2013
We can't test your code, because we need to load your data, and we have to do it with Simulink model

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