problem with the symbolic calculation

Hello! i have a problem: I have a peace of code:
Q1=30;
Q1rad=(pi/180)*Q1;
S1= sym('sin(Q1rad)');
double(S1)
and it doesn.t work because I translate variable to the 'sin(...)' how to make it works? what is the way to calculate expressions with "sin(Q1rad)" and in the end substitute the Q1rad, and calculate the final value of the expression?
best regards! Dmytro.

 Akzeptierte Antwort

Azzi Abdelmalek
Azzi Abdelmalek am 6 Nov. 2013

0 Stimmen

I translate variable to the 'sin(...)' , what doesthat mean?
If you want double(S1), just write:
sin(Q1rad)

5 Kommentare

Dk
Dk am 6 Nov. 2013
Bearbeitet: Azzi Abdelmalek am 6 Nov. 2013
for example, why I can not compute double(C) here?
syms A B C S1 S2 S3;
A=[S1 S2 1;2 3 S2; 3 S1 S3];
B=[S3 S1 1;3 2 S1; 2 S3 S2];
C=A*B;
Q1=30;Q2=20;Q3=10;
Q1rad=(pi/180)*Q1;
Q2rad=(pi/180)*Q2;
Q3rad=(pi/180)*Q3;
S1=sin(Q1rad)
S2=sin(Q2rad)
S3=sin(Q3rad)
double(C)
%Do not put the cart before the horse
syms A B C S1 S2 S3;
Q1=30;Q2=20;Q3=10;
Q1rad=(pi/180)*Q1;
Q2rad=(pi/180)*Q2;
Q3rad=(pi/180)*Q3;
S1=sin(Q1rad)
S2=sin(Q2rad)
S3=sin(Q3rad)
A=[S1 S2 1;2 3 S2; 3 S1 S3];
B=[S3 S1 1;3 2 S1; 2 S3 S2];
C=A*B;
double(C)
Dk
Dk am 6 Nov. 2013
Bearbeitet: Azzi Abdelmalek am 6 Nov. 2013
:DD sorry maybe my questions are a little stupid, but why I can not compute here double(S1) ? or I should change my approach?
Q1=30;
Q1rad=(pi/180)*Q1;
S1= sym('sin(Q1rad)');
double(S1)
Q1=30;
Q1rad=(pi/180)*Q1;
S1= sym('sin(Q1rad)')
double(subs(S1))
Dk
Dk am 6 Nov. 2013
YES) Thank you!

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Andrei Bobrov
Andrei Bobrov am 6 Nov. 2013

0 Stimmen

q = [30;20;10];
S = sind(q);
A = [S(1) S(2) 1;2 3 S(2);3 S(1) S(3)];
B=[S(3) S(1) 1;3 2 S(1); 2 S(3) S(2)];
C = A*B;

Gefragt:

Dk
am 6 Nov. 2013

Kommentiert:

Dk
am 6 Nov. 2013

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