Function of many input arguments returns only one value

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Beaya
Beaya am 27 Okt. 2013
Bearbeitet: Azzi Abdelmalek am 27 Okt. 2013
I have this function:
n = [0 :1: 40], x = 1.0,
v = ((sin(x + 2.^-n) + cos(3*x + 2.^-n)) - (sin(x) + cos(3*x)))/(2.^-n)
It only displays the result for the first value of n and I would like to get the results for all n from 0 to 40. How do I do this? I tried to modify this in many ways but nothing seems to work...

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Azzi Abdelmalek
Azzi Abdelmalek am 27 Okt. 2013
Bearbeitet: Azzi Abdelmalek am 27 Okt. 2013
You missed ./
n = [0 :1: 40], x = 1.0,
v = sin(x + 2.^-n) + cos(3*x + 2.^-n) -(sin(x) + cos(3*x))./(2.^-n)

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