Creating a Filter bank?

6 Ansichten (letzte 30 Tage)
Jason
Jason am 28 Jun. 2011
Hi, I need help with creating a filter bank. Here's some ideas on how my code goes:
% Filter Bank
% Filter parameters are a, b, c, and d
c = [0 1];
for a = 1:5 % 5 different a's
for b = 1:5 % 5 different b's
for d = 1:5 % 5 different d's
filter_bank{a,b,c,d} = filter_function(a,b,c(1),d)+ ...
1i * filter_function(a,b,c(2),d)
end
end
end
It gives me this error: ??? The right hand side of this assignment has too few values to satisfy the left hand side.
Any help is appreciated. Thanks!
Edit1: I think I'll just put down the actual codes here. It's the Gabor Filter function posted on MATLAB Central: File Exchange. I don't know how to properly cite the author's work, so please advise too!
% Copyright (c) 2009, Gao Yang
% All rights reserved
% Gabor Filter parameters
lambda = 8;
theta = 0;
psi = [0 pi/2];
gamma = 0.5;
bw = 1;
N = 8;
for n = 1:N
gb = gabor_fn(bw,gamma,psi(1),lambda,theta)+ 1i * ...
gabor_fn(bw,gamma,psi(2),lambda,theta); % gb is the n-th gabor filter
% Then the filtering goes here
end
Here is the function gabor_fn.
function gb=gabor_fn(bw,gamma,psi,lambda,theta)
% bw = bandwidth, (1)
% gamma = aspect ratio, (0.5)
% psi = phase shift, (0)
% lambda= wave length, (>=2)
% theta = angle in rad, [0 pi)
sigma = lambda/pi*sqrt(log(2)/2)*(2^bw+1)/(2^bw-1);
sigma_x = sigma;
sigma_y = sigma/gamma;
sz=fix(8*max(sigma_y,sigma_x));
if mod(sz,2)==0, sz=sz+1;end
% alternatively, use a fixed size
% sz = 60;
[x y]=meshgrid(-fix(sz/2):fix(sz/2),fix(sz/2):-1:fix(-sz/2));
% x (right +)
% y (up +)
% Rotation
x_theta=x*cos(theta)+y*sin(theta);
y_theta=-x*sin(theta)+y*cos(theta);
gb=exp(-0.5*(x_theta.^2/sigma_x^2+y_theta.^2/sigma_y^2)).*cos(2*pi/lambda*x_theta+psi);
Edit2: Here's what I tried.
for bw = 1:1:8 % total: 8
for gamma = 0.5:0.5:3 % total: 6
for lambda = 1:1:10 % total 10
for theta = 0:pi/6:pi % total: 7
gf_bank{bw,gamma,lambda,theta} = gabor_fn(bw,gamma,psi(1),lambda,theta) + 1i * gabor_fn(bw,gamma,psi(2),lambda,theta);
end
end
end
end
  5 Kommentare
Jason
Jason am 30 Jun. 2011
By the way, forgive me if I am mistaken, I thought it's permissible to modify the code, I just needed to retain the copyright notice. I was needing help with modifying the code to suit the intended application. Is this whole thread inappropriate?
Walter Roberson
Walter Roberson am 30 Jun. 2011
Legally speaking, "all rights reserved" includes prohibiting others from making "derivative works". Look, however, at the download page for that file: a few years ago Mathworks changed their rules to insist that any contributions be under one of the open-source licenses. If the contribution does not predate that change-over, then the open-source license would have been mentioned in the download page and you can use that license.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 28 Jun. 2011
c is a constant array with more than one element, so subscript {a,b,c,d} designates more than one location, but the right hand side only generates a single value.
Warning: using a subscript of 0 is going to lead you to grief...
  11 Kommentare
Jason
Jason am 28 Jun. 2011
Thanks for the reply. Please refer to above, the 'Subscript indices must either be real positive integers or logicals' error points to the line: gf_bank{bw,gamma,lambda,theta} = gabor_fn(bw,gamma,psi(1),lambda,theta) + 1i * gabor_fn(bw,gamma,psi(2),lambda,theta);
Walter Roberson
Walter Roberson am 30 Jun. 2011
gammavals = 0.5:0.5:3;
thetavals = 0:pi/6:pi;
for bw = 1:1:8 % total: 8
for gammaidx = 1:length(gammavals)
for lambda = 1:1:10 % total 10
for thetaidx = 1:length(thetavals)
gf_bank{bw,gammaidx,lambda,thetaidx} = gabor_fn(bw,gammavals(gammaidx),psi(1),lambda,thetavals(thetaidx)) + 1i * gabor_fn(bw,gammavals(gammaidx),psi(2),lambda,thetavals(thetaidx));
end
end
end
end

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Filter Banks finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by