Alvaro García

Aktiv seit 2015

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for loop: Attempted to access y(2); index out of bounds because numel(y)=1. How to solve this error?
a=1; b=2; n=10; h=(b-a)/n; x(1)=a; for i=a:n x(i+1)=x(i)+h; y(i)=x(i).^3; area2(i)=((((y(i)-0)+(y(i+1)-0))/2)*x(...

fast 11 Jahre vor | 1 Antwort | 0

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include a for loop instead of x=a:h:b (h=step size)?
a=1; b=2; n=10; h=(b-a)/n; x=a:h:b; y=x.^3; ya=a.^3; yb=b.^3; area = h/2*(ya+yb+2*(sum(y)-ya-yb)); disp(area) end ...

fast 11 Jahre vor | 1 Antwort | 0

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Problem with for loop
areaneeded=3.75*100.1/100; %disp(areaneeded) %area needed for a 0.1% error a=1; b=2; for n=1:100; h=(b-a)/n...

fast 11 Jahre vor | 1 Antwort | 0

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How can i run the for loop with a stepsize smaller than one?
I have this code: c=0:0.001:1; volume =0.75*pi*c-pi*c.^3; plot(c,volume) n=4; for i=1:4 fu...

fast 11 Jahre vor | 2 Antworten | 0

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if condition not working, any ideas why?
% x=0:0.1:2; y=12*x.^2+10*x-28;%f(x) t=-13*x.^2+15*x+28;%g(x) h=25*x.^2-5*x-56; plot(x,y,'r',x,t,x,h,'b') title('interse...

fast 11 Jahre vor | 1 Antwort | 0

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